Subject: General Aptitude · Chapter: Problems on Numbers · Exam: · Marks: · Difficulty:
The denominator of a fraction is 3 more than the numerator. If the numerator as well as the denominator is increased by 4, the fraction becomes $\frac{4}{5}$. What was the original fraction?
(a)$\frac{8}{11}$
(b)$\frac{5}{8}$
(c)$\frac{10}{13}$
(d)$\frac{7}{10}$
Answer
Answer (as printed): A
Explanation
Let the numerator be $x$. Then, denominator $=x+3$. Now, $\frac{x+4}{(x+3)+4}=\frac{4}{5} \Leftrightarrow 5(x+4)$ $$=4(x+7) \Leftrightarrow x=8 .$$ So, the fraction is $\frac{8}{11}$.
Explanation as extracted from the printed page; notation may be imperfect.