The age of father 10 years ago was thrice the age of his son. 10 years hence father’s age will be twice that… · ABC26GN1805
Subject: General Aptitude · Chapter: Problems on Ages · Exam: L.I.C. 2003
The age of father 10 years ago was thrice the age of his son. 10 years hence father’s age will be twice that of his son. Find the ratio of their present ages.
Answer
No answer key was printed for this question.
Explanation
Let son’s age 10 years ago be x years. Then, father’s age 10 years ago = 3x years. Son’s age 10 years hence = (x + 20) years. Father’s age 10 years hence = (3x + 20) years. ∴ 3x + 20 = 2 (x + 20) ⇒ x = (40 – 20) = 20. Ratio of father’s age and son’s age at present = (3x + 10) : (x + 10) = (3 × 20 + 10) : (20 + 10) = 70 : 30 = 7 : 3.
Explanation as extracted from the printed page; notation may be imperfect.