Subject: General Aptitude · Chapter: Problems on Ages · Exam: 2003 · Marks: · Difficulty:
Tanya's grandfather was 8 times older to her 16 years ago. He would be 3 times of her age 8 years from now. 8 years ago, what was the ratio of Tanya's age to that of her grandfather?
(a)1 : 2
(b)1 : 5
(c)3 : 8
(d)None of these
Answer
Answer (as printed): D
Explanation
16 years ago, let $T=x$ years and $G=8 x$ years. After 8 years from now, $T=(x+16+8)$ years and $G$ $$=(8 x+16+8) \text { years. } \begin{aligned} & \therefore \quad 8 x+24=3(x+24) \\ & \Rightarrow 8 x-3 x=72-24 \\ & \Rightarrow 5 x=48 . \end{aligned}$$ 8years ago, $\frac{T}{G}=\frac{x+8}{8 x+8}=\frac{\frac{48}{5}+8}{8 \times \frac{48}{5}+8}=\frac{48+40}{384+40}=\frac{88}{424}=\frac{11}{53}$.
Explanation as extracted from the printed page; notation may be imperfect.