ABC26GN1907 · Surds and Indices

Subject: General Aptitude · Chapter: Surds and Indices · Exam: · Marks: · Difficulty:

The value of $\left(\frac{32}{243}\right)^{-\frac{4}{5}}$ is
(a)$\frac{4}{9}$
(b)$\frac{9}{4}$
(c)$\frac{16}{81}$
(d)$\frac{81}{16}$
Answer
Answer (as printed): D
Explanation
$\left(\frac{32}{243}\right)^{-\frac{4}{5}}=\left\{\left(\frac{2}{3}\right)^{5}\right\}^{-\frac{4}{5}}=\left(\frac{2}{3}\right)^{5 \times \frac{(-4)}{5}}$

Explanation as extracted from the printed page; notation may be imperfect.

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