If log ₁₀ (x²-6 x+10)=0, then the value of x is · ABC26GN2056
Subject: General Aptitude · Chapter: Logarithms
If $\log _{10}\left(x^{2}-6 x+10\right)=0$, then the value of $x$ is
Answer
Explanation
$\log _{10}\left(x^{2}-6 x+10\right)=0 \Rightarrow\left(x^{2}-6 x+10\right)=10^{0}=1$ $$\begin{aligned} & \Rightarrow x^{2}-6 x+9=0 \\ & \Rightarrow(x-3)^{2}=0 \Rightarrow x=3 . \end{aligned}$$
Explanation as extracted from the printed page; notation may be imperfect.
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