ABC26GN2056 · Logarithms

Subject: General Aptitude · Chapter: Logarithms · Exam: · Marks: · Difficulty:

If $\log _{10}\left(x^{2}-6 x+10\right)=0$, then the value of $x$ is
(a)1
(b)2
(c)3
(d)4
Answer
Answer (as printed): C
Explanation
$\log _{10}\left(x^{2}-6 x+10\right)=0 \Rightarrow\left(x^{2}-6 x+10\right)=10^{0}=1$ $$\begin{aligned} & \Rightarrow x^{2}-6 x+9=0 \\ & \Rightarrow(x-3)^{2}=0 \Rightarrow x=3 . \end{aligned}$$

Explanation as extracted from the printed page; notation may be imperfect.

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