ABC26GN2077 · Logarithms

Subject: General Aptitude · Chapter: Logarithms · Exam: 2003 · Marks: · Difficulty:

If $\log _{10} 7=a$, then $\log _{10}\left(\frac{1}{70}\right)$ is equal to
(a)$-(1+a)$
(b)$(1+a)^{-1}$
(c)$\frac{a}{10}$
(d)$\frac{1}{10 a}$
Answer
Answer (as printed): A
Explanation
$\log _{10}\left(\frac{1}{70}\right)=\log _{10} 1-\log _{10} 70=-\log _{10}$ $$(7 \times 10)=-\left(\log _{10} 7+\log _{10} 10\right)=-(a+1) .$$

Explanation as extracted from the printed page; notation may be imperfect.

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