ABC26GN2084 · Logarithms

Subject: General Aptitude · Chapter: Logarithms · Exam: · Marks: · Difficulty:

If $\log _{10} 2=0.3010$, the value of $\log _{10} 5$ is
(a)0.3241
(b)0.6911
(c)0.6990
(d)0.7525
Answer
Answer (as printed): C
Explanation
$$\begin{aligned} \log _{10} 5 & =\log _{10}\left(\frac{10}{2}\right)=\log _{10} 10-\log _{10} 2=1-\log _{10} 2 \\ & =(1-0.3010)=0.6990 \end{aligned}$$

Explanation as extracted from the printed page; notation may be imperfect.

Open in whiteboard · Browse this chapter in the app