The present population of a village is 5500. If the number of males increases by 11% and the number of females increases by 20%, then the population will become 6330. What is the present population of females in the village?
Answer
Answer (as printed):
Explanation
Let the number of males be $x$. Then, number of females $=(5500-x)$. $$\begin{aligned} & \therefore 111 \% \text { of } x+120 \% \text { of }(5500-x)=6330 \\ & \Rightarrow \frac{111}{100} x+\frac{120}{100}(5500-x)=6330 \\ & \Rightarrow 111 x+660000-120 x=633000 \Rightarrow 9 x=27000 \Rightarrow x=3000 . \end{aligned}$$ Hence, present population of females $=5500-3000=2500$.
Explanation as extracted from the printed page; notation may be imperfect.