Peter got 30% of the maximum marks in an examination and failed by 10 marks. However, Paul who took the same… · ABC26GN2127
Subject: General Aptitude · Chapter: Percentage · Exam: M.B.A. 2007
Peter got 30\% of the maximum marks in an examination and failed by 10 marks. However, Paul who took the same examination got $40\%$ of the total marks and got 15 marks more than the passing marks. What were the passing marks in the examination? (M.B.A., 2007)
Answer
No answer key was printed for this question.
Explanation
Let the maximum marks be $x$. Then, $(30\%$ of $x)+10=(40\%$ of $x)-15 \Rightarrow \frac{30}{100}x+10=\frac{40}{100}x-15 \Rightarrow \frac{10x}{100}=25 \Rightarrow x=250$. Passing marks $=(30\%$ of $250)+10=\left(\frac{30}{100}\times 250\right)+10=85$.
Explanation as extracted from the printed page; notation may be imperfect.