If the numerator of a fraction be increased by 15% and its denominator be diminished by 8%, the value of the fraction is $\frac{15}{16}$. Find the original fraction.
Answer
Answer (as printed):
Explanation
Let the original fraction be $\frac{x}{y}$. Then, $\frac{115 \% \text { of } x}{92 \% \text { of } y}=\frac{15}{16} \Rightarrow \frac{115 x}{92 y}=\frac{15}{16} \Rightarrow \frac{x}{y}=\frac{15}{16} \times \frac{92}{115}=\frac{3}{4}$.
Explanation as extracted from the printed page; notation may be imperfect.