If A earns 33 1/3% more than B, how much percent does B earn less than A? (B.Ed Entrance, 2009) · ABC26GN2141

Subject: General Aptitude · Chapter: Percentage

If A earns $33 \frac{1}{3} \%$ more than B, how much percent does B earn less than A? (B.Ed Entrance, 2009)

Answer

No answer key was printed for this question.

Explanation

Required percentage $=\left(\frac{R}{100+R} \times 100\right) \%=\left(\frac{100 / 3}{400 / 3} \times 100\right) \%=25 \%$.

Explanation as extracted from the printed page; notation may be imperfect.

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