ABC26GN2252 · Percentage

Subject: General Aptitude · Chapter: Percentage · Exam: 2005 · Marks: · Difficulty:

A number increased by $37 \frac{1}{2}$ \% gives 33. The number is
(a)22
(b)24
(c)25
(d)27
Answer
Answer (as printed): B
Explanation
Let the number be $x$. Then, $\left(100+37 \frac{1}{2}\right) \%$ of $x=33$ $\Rightarrow 137 \frac{1}{2} \%$ of $x=33 \Rightarrow \frac{275}{2} \times \frac{1}{100} \times x=33$ $\Rightarrow x=\left(\frac{33 \times 2 \times 100}{275}\right)=24$.

Explanation as extracted from the printed page; notation may be imperfect.

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