The population of a town increased from 1,75,000 to 2,62,500 in a decade. The average percent increase of… · ABC26GN2269
Subject: General Aptitude · Chapter: Percentage
The population of a town increased from 1,75,000 to 2,62,500 in a decade. The average percent increase of population per year is
(a)4.37\%
(b)5\%
(c)6\%
(d)8.75\%
Answer
Explanation
Increase in 10 years $=(262500-175000)=87500$. $$\begin{aligned} & \text { Increase } \%=\left(\frac{87500}{175000} \times 100\right) \%=50 \% . \\ & \therefore \quad \text { Required average }=\left(\frac{50}{10}\right) \%=5 \% . \end{aligned}$$
Explanation as extracted from the printed page; notation may be imperfect.
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