Two students appeared at an examination. One of them secured 9 marks more than the other and his marks was 56\% of the sum of their marks. The marks obtained by them are:
(a)39, 30
(b)41, 32
(c)42, 33
(d)43, 34
Answer
Answer (as printed): C
Explanation
Let their marks be $(x+9)$ and $x$. Then, $x+9=\frac{56}{100}(x+9+x)$ $$\Leftrightarrow \quad 25(x+9)=14(2 x+9) \Leftrightarrow 3 x=99 \Leftrightarrow x=33 .$$ So, their marks are 42 and 33.
Explanation as extracted from the printed page; notation may be imperfect.