ABC26GN2324 · Percentage
Subject: General Aptitude · Chapter: Percentage · Exam: · Marks: · Difficulty:
If $X$ is 90\% of $Y$, then what percent of $X$ is $Y$ ?
(a)90\%
(b)$101 \frac{1}{9} \%$
(c)$111 \frac{1}{9} \%$
(d)190\%
Answer
Explanation
$\mathrm{X}=\frac{90}{100} \mathrm{Y} \Rightarrow \mathrm{X}=\frac{9}{10} \mathrm{Y} \Rightarrow \mathrm{Y}=\frac{10}{9} \mathrm{X} \Rightarrow \frac{\mathrm{Y}}{\mathrm{X}}=\frac{10}{9}$. ∴ Required percentage $$=\left(\frac{Y}{X} \times 100\right) \%=\left(\frac{10}{9} \times 100\right) \%=111 \frac{1}{9} \% .$$
Explanation as extracted from the printed page; notation may be imperfect.
Open in whiteboard · Browse this chapter in the app