ABC26GN2336 · Percentage

Subject: General Aptitude · Chapter: Percentage · Exam: 2006 · Marks: · Difficulty:

( $x \%$ of $y+y \%$ of $x$ ) =?

(a)$x \%$ of $y$

(b)$y \%$ of $x$

(c)2\% of $x y$

(d)$x y \%$ of 3

Answer

Answer (as printed): C

Explanation

$x \%$ of $y+y \%$ of $x=\frac{x}{100} y+\frac{y}{100} x=\frac{2 x y}{100}=2 \%$ of $x y$.

Explanation as extracted from the printed page; notation may be imperfect.