ABC26GN2345 · Percentage
Subject: General Aptitude · Chapter: Percentage · Exam: · Marks: · Difficulty:
If 50\% of $(x-y)=30 \%$ of $(x+y)$, then what percent of $x$ is $y$?
(a)25\%
(b)$33 \frac{1}{3} \%$
(c)40\%
(d)400\%
Answer
Explanation
$50 \%$ of $(x-y)=30 \%$ of $(x+y) \Rightarrow 5(x-y)=3(x+y)$ $\Rightarrow 5 x-5 y=3 x+3 y \Rightarrow 2 x=8 y \Rightarrow y=\frac{x}{4}$. $\therefore$ Required percentage $=\left(\frac{y}{x} \times 100\right) \%=\left(\frac{1}{4} \times 100\right) \%=25 \%$.
Explanation as extracted from the printed page; notation may be imperfect.
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