A spider climbed $62 \frac{1}{2} \%$ of the height of the pole in one hour and in the next hour it covered $12 \frac{1}{2} \%$ of the remaining height. If the height of the pole is 192 m, then distance climbed in second hour is
(a)3 m
(b)5 m
(c)7 m
(d)9 m
Answer
Answer (as printed): D
Explanation
Height climbed in second hour $$\begin{aligned} & =12 \frac{1}{2} \% \text { of }\left(100-62 \frac{1}{2}\right) \% \text { of } 192 \mathrm{m} \\ & =\left(\frac{25}{2} \times \frac{1}{100} \times \frac{75}{2} \times \frac{1}{100} \times 192\right) \mathrm{m}=9 \mathrm{m} \end{aligned}$$