ABC26GN2479 · Percentage

Subject: General Aptitude · Chapter: Percentage · Exam: · Marks: · Difficulty:

A bag contains 600 coins of 25 p denomination and 1200 coins of 50 p denomination. If 12\% of 25 p coins and 24\% of 50 p coins are removed, the percentage of money removed from the bag is nearly
(a)15.6\%
(b)17.8\%
(c)21.6\%
(d)30\%
Answer
Answer (as printed): C
Explanation
Total money $=₹\left(600 \times \frac{25}{100}+1200 \times \frac{50}{100}\right)=₹ 750$. 25 paise coins removed $=\left(\frac{12}{100} \times 600\right)=72.50$ paise coins $$\text { removed }=\left(\frac{24}{100} \times 1200\right)=288 .$$ Money removed $=₹\left(72 \times \frac{25}{100}+288 \times \frac{50}{100}\right)=₹ 162$. ∴ $\quad$ Required percentage $=\left(\frac{162}{750} \times 100\right) \%=21.6 \%$.

Explanation as extracted from the printed page; notation may be imperfect.

Open in whiteboard · Browse this chapter in the app