A bag contains 600 coins of 25 p denomination and 1200 coins of 50 p denomination. If 12% of 25 p coins and… · ABC26GN2479

Total money $=₹\left(600 \times \frac{25}{100}+1200 \times \frac{50}{100}\right)=₹ 750$. 25 paise coins removed $=\left(\frac{12}{100} \times 600\right)=72.50$ paise coins $$\text { removed }=\left(\frac{24}{100} \times 1200\right)=288 .$$ Money removed $=₹\left(72 \times \frac{25}{100}+288 \times \frac{50}{100}\right)=₹ 162$. ∴ $\quad$ Required percentage $=\left(\frac{162}{750} \times 100\right) \%=21.6 \%$.