ABC26GN2488 · Percentage
Subject: General Aptitude · Chapter: Percentage · Exam: · Marks: · Difficulty:
40\% of the people read newspaper X, 50\% read newspaper Y and 10\% read both the papers. What percentage of the people read neither newspaper?
(a)10\%
(b)15\%
(c)20\%
(d)25\%
Answer
Explanation
$n(\mathrm{A})=40, n(\mathrm{B})=50, n(\mathrm{A} \cap \mathrm{B})=10$. $n(\mathrm{A} \cup \mathrm{B})=n(\mathrm{A})+n(\mathrm{B})-n(\mathrm{A} \cap \mathrm{B})$ $$=40+50-10=80 .$$ ∴ Percentage reading either or both newspapers = 80\%. Hence, percentage reading neither newspaper $$=(100-80) \%=20 \% .$$
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