ABC26GN2491 · Percentage

Subject: General Aptitude · Chapter: Percentage · Exam: · Marks: · Difficulty:

There are 600 boys in a hostel. Each plays either hockey or football or both. If 75\% play hockey and 45\% play football, how many play both?

(a)48

(b)60

(c)80

(d)120

Answer

Answer (as printed): D

Explanation

$n(\mathrm{A})=\left(\frac{75}{100} \times 600\right)=450, n(\mathrm{B})=\left(\frac{45}{100} \times 600\right)=270$, $n(\mathrm{A} \cup \mathrm{B})-600$. $$\begin{aligned} \therefore \quad n(A \cap B) & =n(A)+n(B)-n(A \cup B) \\ & =(450+270-600)=120 . \end{aligned}$$

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