ABC26GN2510 · Percentage
Subject: General Aptitude · Chapter: Percentage · Exam: 2015 · Marks: · Difficulty:
$?+30.01 \%$ of $651 \div 25.05 \%$ of $59.98=135$
(a)68
(b)140
(c)122
(d)128.5
Answer
Explanation
Given $(?)+(30.01 \%$ of 651$) \div(25.05 \%$ of 59.98$)=135$ $$\begin{aligned} & \Rightarrow(?)+(30 \% \text { of } 650) \div(25 \% \text { of } 60)=135 \\ & \Rightarrow(?)+\left(\frac{30 \times 650}{100}\right) \div\left(\frac{25 \times 60}{100}\right)=135 \\ & \Rightarrow(?)+(195 \div 15)=135 \\ & \Rightarrow(?)+13=135 \\ & \Rightarrow(?)=(135-13)=122 \end{aligned}$$
Explanation as extracted from the printed page; notation may be imperfect.
Open in whiteboard · Browse this chapter in the app