If 2 x²-7 x y+3 y²=0, then find the value of x: y. · ABC26GN2913
Subject: General Aptitude · Chapter: Ratio and Proportion
If $2 x^{2}-7 x y+3 y^{2}=0$, then find the value of $x: y$.
Answer
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Explanation
$2x^2-7xy+3y^2=0 \Leftrightarrow 2x^2-6xy-xy+3y^2=0$ $$\Leftrightarrow 2x(x-3y)-y(x-3y)=0 \Leftrightarrow (x-3y)(2x-y)=0 \Leftrightarrow x=3y \text{ or } 2x=y$$ $$\Leftrightarrow \frac{x}{y}=3 \text{ or } \frac{x}{y}=\frac{1}{2}. \therefore x:y=3:1 \text{ or } 1:2.$$
Explanation as extracted from the printed page; notation may be imperfect.
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