ABC26GN2938 · Ratio and Proportion

Subject: General Aptitude · Chapter: Ratio and Proportion · Exam: · Marks: · Difficulty:

What should be subtracted from 15, 28, 20 and 38 so that the remaining numbers may be proportional? (M.A.T., 2009)

Answer

Answer (as printed):

Explanation

Let the required number be x. 15 – x 20 – x Then, = 28 – x 38 – x ⇔ (15 – x) (38 – x) = (20 – x) (28 – x) ⇔ 570 – 53x + x2 = 560 – 48x + x2 ⇔ 5x = 10 ⇔ x = 2. Hence, required number = 2.

Explanation as extracted from the printed page; notation may be imperfect.

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