ABC26GN2979 · Ratio and Proportion

Subject: General Aptitude · Chapter: Ratio and Proportion · Exam: · Marks: · Difficulty:

If $\sqrt{2}:(1+\sqrt{3}):: \sqrt{6}: x$, then $x$ is equal to
(a)$\sqrt{3}+3$
(b)$1-\sqrt{3}$
(c)$1+\sqrt{3}$
(d)$\sqrt{3}-3$
Answer
Answer (as printed): A
Explanation
$\sqrt{2}:(1+\sqrt{3}):: \sqrt{6}: x \Leftrightarrow \sqrt{2} x=\sqrt{6}(1+\sqrt{3})$ $\Leftrightarrow x=\frac{\sqrt{6}(1+\sqrt{3})}{\sqrt{2}}=\sqrt{3}(1+\sqrt{3})=\sqrt{3}+3$.

Explanation as extracted from the printed page; notation may be imperfect.

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