ABC26GN2990 · Ratio and Proportion
Subject: General Aptitude · Chapter: Ratio and Proportion · Exam: · Marks: · Difficulty:
If $5 x^{2}-13 x y+6 y^{2}=0$, then $x: y$ is
(a)2 : 1 only
(b)3 : 5 only
(c)5 : 3 or 1 : 2
(d)3 : 5 or 2 : 1
Answer
Explanation
$5 x^{2}-13 x y+6 y^{2}=0 \Rightarrow 5 x^{2}-10 x y-3 x y+6 y^{2}=0 \Rightarrow 5 x$ $$\begin{aligned} & (x-2 y)-3 y(x-2 y)=0 \\ & \Rightarrow(x-2 y)(5 x-3 y)=0 \Rightarrow x=2 y \text { or } 5 x=3 y \\ & \Rightarrow \frac{x}{y}=2 \text { or } \frac{x}{y}=\frac{3}{5} \Rightarrow x: y=2: 1 \text { or } 3: 5 \end{aligned}$$
Explanation as extracted from the printed page; notation may be imperfect.
Open in whiteboard · Browse this chapter in the app