ABC26GN3038 · Ratio and Proportion

Subject: General Aptitude · Chapter: Ratio and Proportion · Exam: · Marks: · Difficulty:

The mean proportional between 0.02 and 0.32 is
(a)0.3
(b)0.08
(c)0.16
(d)0.34
Answer
Answer (as printed): B
Explanation
Required mean proportional $=\sqrt{0.02 \times 0.32}$ $$=\sqrt{0.0064}=0.08 \text {. }$$

Explanation as extracted from the printed page; notation may be imperfect.

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