Subject: General Aptitude · Chapter: Ratio and Proportion · Exam: · Marks: · Difficulty:
The number of students in two sections $A$ and $B$ having different heights is shown in the table given below. \begin{tabular}[t]{|l|l|l|} \hline \multirow{2}{*}{Height (in metres)} & \multicolumn{2}{|c|}{Number of students} \\ \hline & Section A & Section B \\ \hline 1.55 & 3 & 2 \\ \hline 1.60 & 7 & 6 \\ \hline 1.62 & 12 & 14 \\ \hline 1.65 & 15 & 14 \\ \hline 1.68 & 8 & 9 \\ \hline 1.71 & 6 & 5 \\ \hline 1.75 & 3 & 4 \\ \hline \end{tabular} The ratio of the number of students of a particular height in section $A$ to that in section $B$ is the maximum for the height of
(a)1.55 m
(b)1.60 m
(c)1.65 m
(d)1.71 m
Answer
Answer (as printed): A
Explanation
Ratio for different heights (Section A : Section B) is as under: $$\begin{aligned} & 1.55 \rightarrow \frac{3}{2}=1.5 ; 1.60 \rightarrow \frac{7}{6}=1.16 ; 1.62 \rightarrow \frac{12}{14}=\frac{6}{7}=0.86 ; \\ & 1.65 \rightarrow \frac{15}{14}=1.07 ; 1.68 \rightarrow \frac{8}{9}=0.89 ; 1.71 \rightarrow \frac{6}{5}=1.2 ; \\ & 1.75 \rightarrow \frac{3}{4}=0.75 . \end{aligned}$$
Explanation as extracted from the printed page; notation may be imperfect.