Subject: General Aptitude · Chapter: Ratio and Proportion · Exam: · Marks: · Difficulty:
What is the ratio whose terms differ by 40 and the measure of which is $\frac{2}{7}$?
(a)6 : 56
(b)14 : 56
(c)16 : 56
(d)16 : 72
Answer
Answer (as printed): C
Explanation
Let the terms of the ratio be $x$ and $x+40$. Then, $\frac{x}{x+40}=\frac{2}{7} \Rightarrow 7x=2x+80 \Rightarrow 5x=80 \Rightarrow x=16$. $$\therefore \quad \text{Required ratio}=16:56.$$
Explanation as extracted from the printed page; notation may be imperfect.