ABC26GN3334 · Chain Rule

Let the required cost be ₹ $x$. Then, More packets, More cost (Direct Proportion) More weight, More cost (Direct Proportion) $$\left.\begin{array}{l} \left.\begin{array}{l} \text { Packets } \\ \text { Weight } \\ \text { } \end{array}\right)\binom{27}{00}: 1000 \end{array}\right\}:: 28: x$$ $\therefore \quad(16 \times 900 \times x)=(27 \times 1000 \times 28)$ $\Leftrightarrow \quad x=\frac{(27 \times 1000 \times 28)}{16 \times 900}=\frac{105}{2}=52.50$.