A contractor employed 30 men to do a piece of work in 38 days. After 25 days, he employed 5 men more and the work was finished one day earlier. How many days he would have been behind, if he had not employed additional men?
(a)1
(b)$1 \frac{1}{4}$
(c)$1 \frac{3}{4}$
(d)$1 \frac{1}{2}$
Answer
Answer (as printed): A
Explanation
After 25 days, 35 men complete the work in 12 days. Thus, 35 men can finish the remaining work in 12 days. $\therefore$ 30 men can do it in $\frac{12 \times 35}{30} = 14$ days, which is 1 day behind.
Explanation as extracted from the printed page; notation may be imperfect.