12 men complete a work in 9 days. After they have worked for 6 days, 6 more men join them. How many days will… · ABC26GN3517
Subject: General Aptitude · Chapter: Time and Work
12 men complete a work in 9 days. After they have worked for 6 days, 6 more men join them. How many days will they take to complete the remaining work ?
(a)2 days
(b)3 days
(c)4 days
(d)5 days
(e)None of these
Answer
Answer (as printed): A
Explanation
1 man's 1 day's work $=\frac{1}{108}$. 12 men's 6 days' work $=\left(\frac{12}{108} \times 6\right)=\frac{2}{3}$. Remaining work $=\left(1-\frac{2}{3}\right)=\frac{1}{3}$. 18 men's 1 day's work $=\left(\frac{1}{108} \times 18\right)=\frac{1}{6}$. Now, $\frac{1}{6}$ work is done by them in 1 day. $\therefore \frac{1}{3}$ work is done by them in $\left(6 \times \frac{1}{3}\right)=2$ days.
Explanation as extracted from the printed page; notation may be imperfect.