Subject: General Aptitude · Chapter: Time and Work · Exam: · Marks: · Difficulty:
10 men and 15 women together can complete a work in 6 days. It takes 100 days for one man alone to complete the same work. How many days will be required for one woman alone to complete the same work ?
(a)90
(b)125
(c)145
(d)150
(e)None of these
Answer
Answer (as printed): E
Explanation
1 man's 1 day's work $=\frac{1}{100}$. (10 men + 15 women)'s 1 day's work $=\frac{1}{6}$. 15 women's 1 day's work $=\left(\frac{1}{6}-\frac{10}{100}\right)=\left(\frac{1}{6}-\frac{1}{10}\right)=\frac{1}{15}$. $\therefore$ 1 woman's 1 day's work $=\frac{1}{225}$. $\therefore$ 1 woman alone can complete the work in 225 days.
Explanation as extracted from the printed page; notation may be imperfect.