Subject: General Aptitude · Chapter: Time and Distance · Exam: · Marks: · Difficulty:
Sneha is picked up by her father by car from college everyday. The college gets over at 4 p.m. daily. One day, the college got over an hour earlier than usual. Sneha started walking towards her house. Her father, unaware of this fact, leaves his house as usual, meets his daughter on the way, picks her up and they reach the house 15 minutes earlier than usual. What is the ratio of the father’s driving speed to Sneha’s walking speed?
Answer
Answer (as printed):
Explanation
Since 15 minutes are saved, it means that Sneha’s father drives from the meeting point to the college and 15 back to the meeting point in 15 min. i.e. he can drive from the meeting point to the college in = 7.5 min . 2 568 QUANTITATIVE APTITUDE 1 But he reaches the college daily at 4 p.m. So Sneha and her father meet on the way at 3 : 52 p.m. 2 Thus, Sneha walked for 52.5 min and covered the same distance as covered by her father in 7.5 min. Since speed varies inversely as time taken to cover a distance, we have: Father's driving speed 52.5 7 = = . Sneha's walking speed 7.5 1 Hence, required ratio = 7 : 1.
Explanation as extracted from the printed page; notation may be imperfect.