A train running at 7/11 of its own speed reached a place in 22 hours. How much time could be saved if the… · ABC26GN3673
Subject: General Aptitude · Chapter: Time and Distance
A train running at $\frac{7}{11}$ of its own speed reached a place in 22 hours. How much time could be saved if the train would have run at its own speed?
(a)7 hours
(b)8 hours
(c)14 hours
(d)16 hours
Answer
Answer (as printed): B
Explanation
New speed $=\frac{7}{11}$ of usual speed. $$\therefore \quad \text { New time }=\frac{11}{7} \text { of usual time. }$$ So, $\frac{11}{7}$ of usual time $=22 \mathrm{hrs}$ $$\Rightarrow \quad \text { usual time }=\left(\frac{22 \times 7}{11}\right)=14 \mathrm{hrs} .$$ Hence, time saved $=(22-14)=8 \mathrm{hrs}$.
Explanation as extracted from the printed page; notation may be imperfect.