ABC26GN3741 · Time and Distance

Subject: General Aptitude · Chapter: Time and Distance · Exam: 2010 · Marks: · Difficulty:

Two men at points $R$ and $S, 76 \mathrm{km}$ apart, set out at the same time to walk towards each other. The man at $R$ walks uniformly at the rate of $4 \frac{1}{2} \mathrm{km} / \mathrm{hr}$; the man at S walks at the constant rate of $3 \frac{1}{4} \mathrm{km} / \mathrm{hr}$ for the first hour, at $3 \frac{3}{4} \mathrm{km} / \mathrm{hr}$ for the second hour, and so on, in arithmetic progression. If the men meet $x \mathrm{km}$ nearer $R$ than $S$ in an integral number of hours, then $x$ is
(a)4
(b)6
(c)8
(d)10
Answer
Answer (as printed): A
Explanation
No explanation was printed for this question.

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