Subject: General Aptitude · Chapter: Time and Distance · Exam: · Marks: · Difficulty:
Ashok left from place A for place B at 8 a.m. and Rahul left place B for place A at 10.00 a.m. the distance between place A and B is 637 km. If Ashok and Rahul are travelling at a uniform speed of 39kmph and 47 kmph respectively, at what time will they meet?
(a)5 : 30 pm
(b)4 : 30 pm
(c)5 pm
(d)4 pm
Answer
Answer (as printed): B
Explanation
Speed of Ashok = 39 km/ph Speed of Rahul = 47 km/ph Distance between place A and B = 637 km. Distance covered by Ashok (from 8 am to 10 am) in 2 hours $=2\times39=78$ km. ∴ Remaining distance $=637-78=559$. Relative speed $=39+47=86$ km/ph. ∴ Time taken to travel 559 km $=\frac{559}{86}=6.5$ hours. So, they meet at = (10 a.m. + 6.5) hours = 4:30 pm
Explanation as extracted from the printed page; notation may be imperfect.