ABC26GN3995 · Simple Interest
Subject: General Aptitude · Chapter: Simple Interest · Exam: · Marks: · Difficulty:
What annual instalment will discharge a debt of ₹ 1092 due in 3 years at 12\% simple interest ?
Answer
Explanation
Let each instalment be ₹ $x$. Then, $\left(x+\frac{x \times 12 \times 1}{100}\right)+\left(x+\frac{x \times 12 \times 2}{100}\right)+x=1092$ $$\begin{aligned} & \Leftrightarrow \quad \frac{28 x}{25}+\frac{31 x}{25}+x=1092 \Leftrightarrow(28 x+31 x+25 x)=(1092 \times 25) \\ & \Leftrightarrow \quad x=\left(\frac{1092 \times 25}{84}\right)=325 . \end{aligned}$$ ∴ Each instalment $=₹ 325$.
Explanation as extracted from the printed page; notation may be imperfect.
Open in whiteboard · Browse this chapter in the app