A man borrows ₹ 12,500 at 20% compound interest. At the end of every year he pays ₹ 2000 as part repayment… · ABC26GN4201

Balance $$\begin{aligned} & =₹\left[\left\{12500 \times\left(1+\frac{20}{100}\right)^{3}\right\}-\left\{\begin{array}{r} 2000 \times\left(1+\frac{20}{100}\right)^{2} \\ +2000 \times\left(1+\frac{20}{100}\right)+2000 \end{array}\right\}\right] \\ & =₹\left[\left(12500 \times \frac{6}{5} \times \frac{6}{5} \times \frac{6}{5}\right)-\binom{2000 \times \frac{6}{5} \times \frac{6}{5}}{+2000 \times \frac{6}{5}+2000}\right] \\ & =₹[21600-(2880+2400+2000)]=₹ 14320 . \end{aligned}$$