ABC26GN4290 · Area

Subject: General Aptitude · Chapter: Area · Exam: · Marks: · Difficulty:

Find the ratio of the areas of the incircle and circumcircle of a square.
Answer
Answer (as printed):
Explanation
Let the side of the square be $x$. Then, its diagonal $=\sqrt{2} x$. $$\begin{aligned} & \text { Radius of incircle }=\frac{x}{2} \text { and radius of circumcircle }=\frac{\sqrt{2} x}{2}=\frac{x}{\sqrt{2}} . \\ & \therefore \text { Required ratio }=\left(\frac{\pi x^{2}}{4}: \frac{\pi x^{2}}{2}\right)=\frac{1}{4}: \frac{1}{2}=1: 2 . \end{aligned}$$

Explanation as extracted from the printed page; notation may be imperfect.

Open in whiteboard · Browse this chapter in the app