Subject: General Aptitude · Chapter: Area · Exam: 2003 · Marks: · Difficulty:
The difference between the length and breadth of a rectangle is 23 m . If its perimeter is 206 m, then its area is
(a)$1520 \mathrm{m}^{2}$
(b)$2420 \mathrm{m}^{2}$
(c)$2480 \mathrm{m}^{2}$
(d)$2520 \mathrm{m}^{2}$
Answer
Answer (as printed):
Explanation
We have : $(l-b)=23$ and $2(l+b)=206$ or $(l+b)=103$. Solving the two equations, we get : $l=63$ and $b=40$. ∴ Area $=(l \times b)=(63 \times 40) \mathrm{m}^{2}=2520 \mathrm{m}^{2}$.