A rectangular paper, when folded into two congruent parts had a perimeter of 34 cm for each part folded along… · ABC26GN4322
Subject: General Aptitude · Chapter: Area
A rectangular paper, when folded into two congruent parts had a perimeter of 34 cm for each part folded along one set of sides and the same is 38 cm when folded along the other set of sides. What is the area of the paper?
(a)$140 \mathrm{cm}^{2}$
(b)$240 \mathrm{cm}^{2}$
(c)$560 \mathrm{cm}^{2}$
(d)None of these
Answer
No answer key was printed for this question.
Explanation
When folded along breadth, we have : $2\left(\frac{l}{2}+b\right)=34$ or $l+2 b=34$ When folded along length, we have : $2\left(l+\frac{b}{2}\right)=38$ or $2 l+b=38$ Solving (i) and (ii), we get : $l=14$ and $b=10$. ∴ Area of the paper $=(14 \times 10) \mathrm{cm}^{2}=140 \mathrm{cm}^{2}$.