Subject: General Aptitude · Chapter: Area · Exam: · Marks: · Difficulty:
A lawn is in the shape of a rectangle of 80 m length and 50 m width. Outside the lawn there is a footpath of uniform 1 m width bordering the lawn. The area of the footpath is
(a)$264 \mathrm{m}^{2}$
(b)$284 \mathrm{m}^{2}$
(c)$4000 \mathrm{m}^{2}$
(d)$4264 \mathrm{m}^{2}$
Answer
Answer (as printed): A
Explanation
Area of the footpath $=\left[\{(80+2) \times(50+2\}-(80 \times 50)] \mathrm{m}^{2}\right.$ $$=[(82 \times 52)-(80 \times 50)] \mathrm{m}^{2}=(4264-4000) \mathrm{m}^{2}=264 \mathrm{m}^{2} .$$