A rectangular garden (60 m × 40 m) is surrounded by a road of width 2 m, the road is covered by tiles and the… · ABC26GN4368
Subject: General Aptitude · Chapter: Area · Exam: Hotel Management 2007
A rectangular garden (60 m × 40 m) is surrounded by a road of width 2 m, the road is covered by tiles and the garden is fenced. If the total expenditure is ₹ 51600 and rate of fencing is ₹ 50 per metre, then the cost of covering 1 sq. m of road by tiles is
(a)₹ 10
(b)₹ 50
(c)₹ 100
(d)₹ 150
Answer
Answer (as printed): C
Explanation
Length of the fence $=2(60+40) \mathrm{m}=200 \mathrm{m}$. Cost of fencing $=₹(200 \times 50)=₹ 10000$. Area of the road $=[(64 \times 44)-(60 \times 40)] \mathrm{m}^{2}$ $$=(2816-2400) \mathrm{m}^{2}=416 \mathrm{m}^{2} .$$ Let the cost of tiling the rood be ₹ $x$ per sq. m. $$\therefore 416 x+10000=51600 \Rightarrow 416 x=41600 \Rightarrow x=₹ 100 .$$