Subject: General Aptitude · Chapter: Area · Exam: 2005 · Marks: · Difficulty:
Perimeter of a rectangular field is 160 metres and the difference between its two adjacent sides is 48 metres. The side of a square field, having the same area as that of the rectangle, is
(a)4 m
(b)8 m
(c)16 m
(d)32 m
Answer
Answer (as printed): D
Explanation
Let the sides of the rectangle be $x$ metres and $(x+48)$ metres. Then, $2(x+x+48)=160 \Rightarrow 4 x+96=160 \Rightarrow 4 x=64$ $\Rightarrow x=16$. So, sides of the rectangle are 16 m and 64 m. Area of the rectangle $=(16 \times 64) \mathrm{m}^{2}=1024 \mathrm{m}^{2}$. Area of the square $=1024 \mathrm{m}^{2}$. ∴ Side of the square $=\sqrt{1024} \mathrm{m}=32 \mathrm{m}$.