Subject: General Aptitude · Chapter: Area · Exam: 2008 · Marks: · Difficulty:
The perimeter of an isosceles triangle is equal to 14 cm and the lateral side is to the base in the ratio 5 : 4. The area of the triangle is
(a)$21 \mathrm{cm}^{2}$
(b)$0.5 \sqrt{21} \mathrm{cm}^{2}$
(c)$1.5 \sqrt{21} \mathrm{cm}^{2}$
(d)$2 \sqrt{21} \mathrm{cm}^{2}$
Answer
Answer (as printed): D
Explanation
Let the sides of the triangle be $5 x, 5 x$ and $4 x$ cm respectively. Then, $5 x+5 x=4 x+14$ or $14 x=14$ or $x=1$. So, $a=5 \mathrm{cm}, b=5 \mathrm{cm}, c=4 \mathrm{cm}$.