ABC26GN4462 · Area
Subject: General Aptitude · Chapter: Area · Exam: · Marks: · Difficulty:
If three sides of a triangle are 6 cm, 8 cm and 10 cm, then the altitude of the triangle, using the largest side as its base, will be
(a)4.4 cm
(b)4.8 cm
(c)6 cm
(d)8 cm
Answer
Explanation
$a=6 \mathrm{cm}, b=8 \mathrm{cm}, c=10 \mathrm{cm}$. So, $s=\frac{6+8+10}{2}=12 \mathrm{cm}$. $$\text { Area of the triangle }=\sqrt{12 \times 6 \times 4 \times 2} \mathrm{cm}^{2}=24 \mathrm{cm}^{2} .$$ Let the length of the required altitude be $x$ cm. $$\text { Then, } \frac{1}{2} \times 10 \times x=24 \Rightarrow x=\frac{24 \times 2}{10}=\left(\frac{48}{10}\right) \mathrm{cm}=4.8 \mathrm{cm} \text {. }$$
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