ABC26GN4468 · Area

Subject: General Aptitude · Chapter: Area · Exam: 2007 · Marks: · Difficulty:

A triangle of area $9 y \mathrm{cm}^{2}$ has been drawn such that its area is equal to the area of an equilateral triangle of side 6 cm . The value of $y$ would be
(a)$\sqrt{2}$
(b)$\sqrt{3}$
(c)2
(d)3
Answer
Answer (as printed): B
Explanation
$9 y=\frac{\sqrt{3}}{4} \times 6 \times 6 \Rightarrow y=\left(\frac{\sqrt{3}}{4} \times 6 \times 6 \times \frac{1}{9}\right)=\sqrt{3}$.

Explanation as extracted from the printed page; notation may be imperfect.

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