Subject: General Aptitude · Chapter: Area · Exam: 2007 · Marks: · Difficulty:
The base and altitude of a right-angled triangle are 12 cm and 5 cm respectively. The perpendicular distance of its hypotenuse from the opposite vertex is
(a)$4 \frac{4}{13} \mathrm{cm}$
(b)$4 \frac{8}{13} \mathrm{cm}$
(c)5 cm
(d)7 cm
Answer
Answer (as printed): B
Explanation
Area of the triangle $=\left(\frac{1}{2} \times 12 \times 5\right) \mathrm{cm}^{2}=30 \mathrm{cm}^{2}$. $$\text { Hypotenuse }=\sqrt{(12)^{2}+5^{2}} \mathrm{cm}=\sqrt{169} \mathrm{cm}=13 \mathrm{cm} \text {. }$$