Subject: General Aptitude · Chapter: Area · Exam: · Marks: · Difficulty:
If the area of a square with side $a$ is equal to the area of a triangle with base $a$, then the altitude of the triangle is
(a)$\frac{a}{2}$
(b)$a$
(c)$2 a$
(d)$4 a$
Answer
Answer (as printed): C
Explanation
Area of a square with side $a=a^{2}$ sq. units. Area of a triangle with base. $$\begin{aligned} & =a=\left(\frac{1}{2} \times a \times h\right) \text { sq. units } \\ & \therefore \quad a^{2}=\frac{1}{2} \times a \times h \Leftrightarrow h=2 a . \end{aligned}$$ Hence, the altitude of the triangle is $2 a$.
Explanation as extracted from the printed page; notation may be imperfect.